Z^333-2.2z^2+1.5z-0.35=0

Solution for Z^333-2.2z^2+1.5z-0.35=0 equation:

^333-2.2Z^2+1.5Z-0.35=0

We add all the numbers together, and all the variables

-2.2Z^2+1.5Z=0

a = -2.2; b = 1.5; c = 0;
Δ = b2-4ac
Δ = 1.52-4·(-2.2)·0
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{2.25}}{2*-2.2}=\frac{-1.5-\sqrt{2.25}}{-4.4}
$
$Z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{2.25}}{2*-2.2}=\frac{-1.5+\sqrt{2.25}}{-4.4}
$